4^1+2x=16^-2+x/2x

Solution for 4^1+2x=16^-2+x/2x equation:

4^1+2x=16^-2+x/2x

We move all terms to the left:

4^1+2x-(16^-2+x/2x)=0


Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-(16^-2+x/2x)+4=0

We get rid of parentheses

2x-x/2x+2+4-16^=0

We multiply all the terms by the denominator


2x*2x-x+2*2x+4*2x-16^*2x=0

We add all the numbers together, and all the variables

-1x+2x*2x+2*2x+4*2x-16^*2x=0

Wy multiply elements

4x^2-32x^2-1x+4x+8x=0

We add all the numbers together, and all the variables

-28x^2+11x=0

a = -28; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-28)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-28}=\frac{-22}{-56}
=11/28
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-28}=\frac{0}{-56}
=0
$